Choice without forwarding the passage?

Question

I'm curious if this is possible.

I can do it using links and widgets by:

link still exist unless the selector is replaced or removed.
<<link "add 1 strength">>
 <<display change>>
<</link>>

deactivates the link and change the text.
<<linkreplace "1 strength added">>
  add 1 strength
<</linkreplace>>

However doing those for multiple choices are not efficient.

Like:

@@#group1;
<<link "choice 1">>
 choice 1
 <<replace "#group1">>
   Chosen 1
 <</replace>>
<</link>>
<<link "choice 2">>
 choice 2
 <<replace "#group1">>
   Chosen 2
 <</replace>>
<</link>>
<<link "choice 3">>
 choice 3
 <<replace "#group1">>
   Chosen 3
 <</replace>>
<</link>>
@@

@@#group2;
<<linkreplace "choice 1">>
 choice 1
 <<replace "#group2">>
  Chosen 1
 <</replace>>
<</linkreplace>>
<<linkreplace "choice 2">>
 choice 2
 <<replace "#group2">>
  Chosen 2
 <</replace>>
<</linkreplace>>
<<linkreplace "choice 3">>
 choice 3
 <<replace "#group2">>
 Chosen 3
 <</replace>>
<</linkreplace>>
@@

I learned how to use widget, its so nifty!

Edit to add:

Also to display the next paragraphs on the same passage with the choices/links.

Example:

Clicked choice 1 -- renders codes/displays for choice 1

Then continue on to the next paragraphs not passage.

It would be easy to just make and include another passage but i'd rather have them in one passage.

Answer 1

You can use a <<for>> loop. Not sure that'd be more efficient though. For example:

<<set $test to 0>>
<<set $choices to ["<<set $test++>>$test", "<<set $test+=2>>$test", "<<set $test+=3>>$test"]>>

@@#group1;
<<nobr>>
<<for _i to 0; _i lt $choices.length; _i++>>

<<set _j to _i + 1>>

<<capture $choices[_i]>>
<<link "choice _j">>
<<replace "#group1">>$choices[_i]<</replace>>
<</link>>
<</capture>>

<br>

<</for>>
<</nobr>>
@@

 

Comments

Oh thanks! I can use that for populating the choices instead of manualling typing them.

This is what I'm trying to accomplish.

I'm using widgets for the choices.